How do you write the balanced equation for the hydration of #CuSO_4#?

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Answer 1 · 2016-11-15T23:21:33

#"CuSO"_4"(s)" + "5H"_2"O(l)" → "CuSO"_4·"5H"_2"O(s)"#

The formula for the hydrated #"CuSO"_4# is #"CuSO"_4·"5H"_2"O"#.

The unbalanced equation is

#"CuSO"_4"(s)" + "H"_2"O(l)" → "CuSO"_4·"5H"_2"O(s)"#

To balance it, put a 5 in front of #"H"_2"O"#.

This gives the balanced equation

#"CuSO"_4"(s)" + "5H"_2"O(l)" → "CuSO"_4·"5H"_2"O(s)"#