How do you write the balanced neutralization equation for the reaction between acetic acid and sodium hydroxide?

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How do you write the balanced neutralization equation for the reaction between acetic acid and sodium hydroxide?

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Answer 1 · 2018-01-19T17:35:32

$C_{2} H_{4} O_{2} + N a O H = C_{2} H_{3} O_{2} N a + H_{2} O$ $C_2H_4O_2 + NaOH = C_2H_3O_2Na + H_2O$

Explanation:

acetic acid (ethanoic acid): $C H_{3} C O O H$ $CH_3COOH$

$C H_{3} C O O H = C_{2} H_{4} O_{2}$ $CH_3COOH = C_2H_4O_2$

sodium hydroxide: $N a O H$ $NaOH$

neutralisation reactions always produce a salt and water.

in this case, the salt is sodium ethanoate
( $C H_{3} C O O N a, C_{2} H_{3} O_{2} N a$ $CH_3COONa, C_2H_3O_2Na$ )

equation:

$C_{2} H_{4} O_{2} + N a O H = C_{2} H_{3} O_{2} N a + H_{2} O$ $C_2H_4O_2 + NaOH = C_2H_3O_2Na + H_2O$

carbon: $2$ $2$ on the left, $2$ $2$ on the right
sodium: $1$ $1$ on the left, $1$ $1$ on the right
hydrogen: $5$ $5$ on the left, $5$ $5$ on the right
oxygen: $3$ $3$ on the left, $3$ $3$ on the right.

this means that the equation is balanced, with $1 : 1 : 1 : 1$ $1:1:1:1$ ratio.

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How do you write the balanced neutralization equation for the reaction between acetic acid and sodium hydroxide?

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