How do you write the equation $2 = r cos (θ + π)$ $2=rcos(theta+pi)$ in rectangular form?

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Answer 1 · 2017-02-19T10:44:09

$x = - 2$ $x=-2$

The conversion formula is $r (cos θ, sin θ) = (x, y)$ $r(costheta, sintheta)=(x, y)$ .

Now, $2 = r cos (θ + π) = - r cos θ = - x$ $2 = rcos(theta+pi)=-rcostheta=-x$

How do you write the equation 2=rcos(theta+pi)2=rcos(θ+π)2=rcos(theta+pi) in rectangular form?