How do you write the equation $- \frac{4}{3} = tan x$ $-4/3=tanx$ in the form of an inverse function?

Question

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Answer 1 · 2017-10-22T15:39:28

See other answer.

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Answer 2 · 2017-10-23T00:47:16

Please see below.

$tan a = b$ $tan a = b$ if and only of $a = {tan}^{- 1} (b) + π k$ $a = tan^-1(b) + pik$ for some integer $k$ $k$ .

So

$x = {tan}^{- 1} (- \frac{4}{3}) + π k$ $x = tan^-1(-4/3) + pik$ for integer $k$ $k$

How do you write the equation -4/3=tanx−43=tanx-4/3=tanx in the form of an inverse function?