How do you write the equation $4 x - 5 y = 10$ $4x-5y=10$ in polar form?

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Answer 1 · 2016-12-10T14:49:58

The equation is $r = \frac{10}{4 cos θ - 5 sin θ}$ $r=10/(4costheta-5sintheta)$

To convert from cartesian coordinates $(x, y)$ $(x,y)$ to polar coordinates $(r, θ)$ $(r,theta)$ , we use the following equations

$x = r cos θ$ $x=rcostheta$

$y = r sin θ$ $y=rsintheta$

$x^{2} + y^{2} = r^{2}$ $x^2+y^2=r^2$

Here the equation is

$4 x - 5 y = 10$ $4x-5y=10$

$4 r cos θ - 5 r sin θ = 10$ $4rcostheta-5rsintheta=10$

$r (4 cos θ - 5 sin θ) = 10$ $r(4costheta-5sintheta)=10$

$r = \frac{10}{4 cos θ - 5 sin θ}$ $r=10/(4costheta-5sintheta)$

How do you write the equation 4x-5y=104x−5y=104x-5y=10 in polar form?