How do you write the equation for the graph obtained when the parent graph is #y=x^3# and it is translated 4 unites left and 7 units down?

1 Answer
Nov 29, 2016

The equation of the transformed graph would be: #y+7 = (x+4)^3#

Explanation:

Consider the parent graph #y=x^3#

The first transforamtion is 4 units left #-> # replace #x# with #(x+4)#

The second transformation is 7 unit down #-># replace #y# with #(y+7)#

Hence: The equation of the transformed graph would be: #y+7 = (x+4)^3#

The graph of the transformed #y# is shown below:

graph{(x+4)^3-7 [-25.66, 25.66, -12.83, 12.82]}