How do you write the equation in point slope form given point (6,1) and perpendicular to y=-x+6?
1 Answer
May 13, 2018
Explanation:
#"the equation of a line in "color(blue)"slope-intercept form"# is.
#•color(white)(x)y=mx+b#
#"where m is the slope and b the y-intercept"#
#y=-x+6" is in this form"#
#"with slope m "=-1#
#"given a line with slope m then the slope of a line"#
#"perpendicular to it is"#
#•color(white)(x)m_(color(red)"perpendicular")=-1/m#
#rArrm_("perpendicular")=-1/(-1)=1#
#"the equation of a line in "color(blue)"point-slope form"# is.
#•color(white)(x)y-y_1=m(x-x_1)#
#"where m is the slope and "(x_1,y_1)" a point on the line"#
#"here "m=1" and "(x_1,y_1)=(6,1)#
#rArry-1=1(x-6)larrcolor(red)"in point-slope form"#