How do you write the equation in slope intercept form given $3 x - 2 y = - 6$ $3x - 2y = -6$ ?

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Answer 1 · 2018-05-10T14:57:23

$y = \frac{3}{2} x + 3$ $y=3/2x+3$

The slope intercept form of a line is given as:

$y = m x + b$ $y=mx+b$

Where:

$m$ $bbm$ is the gradient and $b$ $bb(b)$ is the y axis intercept.

Our task is to rearrange our function so it is in the same form.

$3 x - 2 y = - 6$ $3x-2y=-6$

Subtract $3 x$ $3x$ from both sides:

$3 x - 3 x - 2 y = - 6 - 3 x$ $3x-3x-2y=-6-3x$

$- 2 y = - 6 - 3 x$ $-2y=-6-3x$

Divide both sides by $- 2$ $-2$

$(-2y)/(-2)=(-6)/(-2) \ \ (-3x)/(-2)$

$y=3+3/2x$

$y=3/2x+3$

How do you write the equation in slope intercept form given 3x - 2y = -63x−2y=−63x - 2y = -6?