How do you write the equation in slope intercept form given $- 5 x + 7 y = 1$ $-5x + 7y = 1$ ?

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Answer 1 · 2017-02-07T04:56:04

$y = \frac{5}{7} x + \frac{1}{7}$ $y = color(red)(5/7)x + color(blue)(1/7)$

The slope-intercept form of a linear equation is: $y = m x + b$ $y = color(red)(m)x + color(blue)(b)$

Where $m$ $color(red)(m)$ is the slope and $b$ $color(blue)(b)$ is the y-intercept value.

We need to solve for $y$ $y$ as follows:

$5 x - 5 x + 7 y = 5 x + 1$ $color(red)(5x) - 5x + 7y = color(red)(5x) + 1$

$0 + 7 y = 5 x + 1$ $0 + 7y = 5x + 1$

$7 y = 5 x + 1$ $7y = 5x + 1$

$\frac{7 y}{7} = \frac{5 x + 1}{7}$ $(7y)/color(red)(7) = (5x + 1)/color(red)(7)$

$(color(red)(cancel(color(black)(7)))y)/cancel(color(red)(7)) = (5x)/7 + 1/7$

$y = color(red)(5/7)x + color(blue)(1/7)$

How do you write the equation in slope intercept form given -5x + 7y = 1−5x+7y=1-5x + 7y = 1?