How do you write the equation in slope intercept form given x-3y=6?

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Answer 1 · 2017-04-08T17:13:48

#y = 1/3x - 2#

Given: #x - 3y = 6#

Put in slope-intercept form #y = mx + b#:

Add #3y# to both sides of the equation to make it positive:

#x - 3y + 3y = 6 + 3y#
#x = 6 + 3y#

Subtract #6# from both sides of the equation:

#x - 6 = 6 - 6 + 3y#
#x - 6 = 3y#

Divide both sides of the equation by #3#:

#x/3 - 6/3 = (3y)/3#
#1/3x - 2 = y#

So #y = 1/3x - 2#