How do you write the equation in slope intercept form given $y - 4 = (x + 8)$ $y − 4 = (x + 8)$ ?

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Answer 1 · 2016-03-03T00:34:46

I got: $y = x + 12$ $y=x+12$

The general Slope-Intercept form is:
$y = m x + c$ $y=mx+c$
where:
$m =$ $m=$ slope
$c =$ $c=$ y-intercept
are two real numbers.

We want to get to this particular form, so we, basically, isolate $y$ $y$ :

$y = (x + 8) + 4$ $y=(x+8)+4$

Transferring the $- 4$ $-4$ from left to right and changing its sign.

We then get:

$y = x + 8 + 4$ $y=x+8+4$
$y = x + 12$ $y=x+12$
which is in the form: $y = m x + c$ $y=mx+c$

How do you write the equation in slope intercept form given y−4=(x+8)y − 4 = (x + 8)?