How do you write the equation #log_7 (1/2401)=-4# into exponential form? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Shell Dec 20, 2016 #7^-4=1/2401# Explanation: Write #log_7(1/2401)=-4# as an exponential. Use the rule #log_bx=a color(white)(aa)=> color(white)(aa)x=b^a# #log_7(1/2401)=-4color(white)(aa)=>color(white)(aa)7^-4=1/2401# Note that the #7# is the base of the log and the base of the exponential. And, the "answer" to a log equation is the exponent of the exponential. Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 6859 views around the world You can reuse this answer Creative Commons License