How do you write the equation ${log}_{\sqrt{6}} 36 = 4$ $log_sqrt6 36=4$ into exponential form?

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Answer 1 · 2017-01-21T20:59:33

First, recognize that your base is $\sqrt{6}$ $sqrt(6)$ , and the power is 4.

The exponential form is ${\sqrt{6}}^{4} = 36$ $sqrt(6)^4 = 36$ .

To check, multiply $\sqrt{6} \cdot \sqrt{6} \cdot \sqrt{6} \cdot \sqrt{6}$ $sqrt(6)*sqrt(6)*sqrt(6)*sqrt(6)$ which = 36.

How do you write the equation log√636=4log_sqrt6 36=4 into exponential form?