How do you write the equation of a line that passes through (1,1) and has slope 1/4?

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Answer 1 · 2015-04-01T12:26:25

y-1= $\frac{1}{4}$ $1/4$ (x-1)

Answer 2 · 2015-04-07T08:18:45

$(y - k) = m \cdot (x - h)$ $(y-k)=m*(x-h)$
$m$ $m$ is the Slope of the Line

$(h, k)$ $(h,k)$ are the co-ordinates of any point on that Line.

Here, we have been given the coordinates $(h, k)$ $(h,k)$ of 1 point on that line as $(1, 1)$ $(1,1)$
And the Slope $m$ $m$ is given as $\frac{1}{4}$ $1/4$

Substituting the values of h, k and m in the Point-Slope form, we get

$(y - 1) = (\frac{1}{4}) \cdot (x - 1)$ $(y-1)=(1/4)*(x-1)$
The above will be the Equation of the Line in Point-Slope form.

Multiplying both sides with 4, we get:

$4 \cdot (y - 1) = x - 1$ $4*(y-1)=x-1$

$4 y - 4 = x - 1$ $4y-4=x-1$

$4 y = x - 1 + 4$ $4y=x-1+4$

$4 y = x + 3$ $4y=x+3$

We get the equation of the line as :
$y = (\frac{1}{4}) \cdot x + \frac{3}{4}$ $y=(1/4)*x+3/4$

The graph will look like this:

graph{y=(1/4)*x+3/4 [-10, 10, -5, 5]}