How do you write the equation of a line that passes through the point (3, -6) and has a slope of 4?
1 Answer
May 20, 2017
Explanation:
#"the equation of a line in "color(blue)"point-slope form "# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represent the slope and# (x_1,y_1)" a point on the line"#
#"here " m=4" and " (x_1,y_1)=(3,-6)#
#y-(-6)=4(x-3)#
#rArry+6=4(x-3)larrcolor(red)" in point-slope form"#
#"distributing and simplifying gives another version"#
#y+6=4x-12#
#rArry=4x-12-6#
#rArry=4x-18larrcolor(red)" in slope-intercept form"#