How do you write the equation of a line that passes through the point (3, -6) and has a slope of 4?
1 Answer
May 20, 2017
Explanation:
"the equation of a line in "color(blue)"point-slope form "the equation of a line in point-slope form is.
color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))
where m represent the slope and(x_1,y_1)" a point on the line"
"here " m=4" and " (x_1,y_1)=(3,-6)
y-(-6)=4(x-3)
rArry+6=4(x-3)larrcolor(red)" in point-slope form"
"distributing and simplifying gives another version"
y+6=4x-12
rArry=4x-12-6
rArry=4x-18larrcolor(red)" in slope-intercept form"