How do you write the equation of a line that passes through the point (3, -6) and has a slope of 4?

1 Answer
May 20, 2017

y=4x-18y=4x18

Explanation:

"the equation of a line in "color(blue)"point-slope form "the equation of a line in point-slope form is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))
where m represent the slope and (x_1,y_1)" a point on the line"

"here " m=4" and " (x_1,y_1)=(3,-6)

y-(-6)=4(x-3)

rArry+6=4(x-3)larrcolor(red)" in point-slope form"

"distributing and simplifying gives another version"

y+6=4x-12

rArry=4x-12-6

rArry=4x-18larrcolor(red)" in slope-intercept form"