How do you write the equation of a line that passes through the point (7, -2) and has a slope of -3?

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Answer 1 · 2018-03-22T17:37:44

#y=-3x+19#

We know that the equation of a line is #y=mx+c#

It is given that the slope is -3 so #m=-3#

This gives us,

#y=-3x+c#

To find the value of c, we put In the point given to us.

#(-2)=-3*(7)+c#

#-2=-21+c# and hence #c=19#

This gives is the final equation as #y=-3x+19#