How do you write the equation of the cosine function with an amplitude of 2 and a period of 3pi/5?
1 Answer
Sep 17, 2016
Explanation:
The standard form of the
#color(blue)"cosine function"# is
#color(red)(bar(ul(|color(white)(a/a)color(black)(y=acos(bx+c)+d)color(white)(a/a)|)))# where amplitude = |a| and period
#=(2pi)/b# phase shift
#=-c/b" and " d=" vertical shift"# here amplitude = 2 and period
#=(3pi)/5#
#rArrb=(2pi)/((3pi)/5)=2cancel(pi)xx5/(3cancel(pi))=10/3#
#rArry=2cos(10/3x)" is the equation"#
