How do you write the equation using function notation that goes through (-2,-5); perpendicular to $3 x + 5 y = - 17$ $3x + 5y = -17$ ?

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How do you write the equation using function notation that goes through (-2,-5); perpendicular to $3 x + 5 y = - 17$ $3x + 5y = -17$ ?

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Answer 1 · 2015-05-24T13:21:45

$3 x + 5 y = - 17$ $3x+5y = -17$
can be written in slope-intercept form as
$y = - \frac{3}{5} x - 71$ $y = -3/5x -71$
which has a slope of $- \frac{3}{5}$ $-3/5$

Any line perpendicular to this will have a slope $\frac{5}{3}$ $5/3$

A line going through $(- 2, - 5)$ $(-2,-5)$ with a slope of $\frac{5}{3}$ $5/3$
is given by
$y + 5 = \frac{5}{3} (x + 2)$ $y+5 = 5/3(x+2)$

$y = \frac{5 x}{3} + \frac{10}{3} - 5$ $y= (5x)/3 + 10/3 -5$

$y = \frac{5 x - 5}{3} = \frac{5}{3} (x - 1)$ $y = (5x-5)/3 = 5/3(x-1)$
or
$f (x) = \frac{5}{3} (x - 1)$ $f(x) = 5/3(x-1)$

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How do you write the equation using function notation that goes through (-2,-5); perpendicular to $3 x + 5 y = - 17$ $3x + 5y = -17$ ?

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Math

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How do you write the equation using function notation that goes through (-2,-5); perpendicular to 3x+5y=−173x + 5y = -17?

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How do you write the equation using function notation that goes through (-2,-5); perpendicular to $3 x + 5 y = - 17$ $3x + 5y = -17$ ?