Question

How do you write the expression for the nth term of the sequence given `2/1, 3/3, 4/5, 5/7, 6/9,...`?

Answer 1

If we take `2/1` as the first term, and see that the numerators differ `1` and the denominators differ `2`.

Explanation:

`t_n=(1+1xxn)/(1+2xx(n-1))=(n+1)/(2n-1)`