Question

How do you write the quadratic function in standard form `y=2/3(x-9)^2-4`?

Answer 1

`y = 2/3x^2 - 12x + 50`

Explanation:

Given: `y = 2/3(x - 9)^2 - 4`

Distribute using `(a + b)^2 = a^2 + 2ab + b^2`

`y = 2/3(x^2 -18x + 81) - 4`

`y = 2/3x^2 - 2/3 * 18/1 x + 2/3 * 81/1 - 4`

`y = 2/3x^2 -12 x + 54 - 4`

`y = 2/3x^2 - 12x + 50`