How do you write the series $2+12+72+432+2592$ using sigma notation?

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Answer 1 · 2016-11-16T18:01:15

The answer is $=sum_0^n2*6^n$

This is a geometric series,

$S=a+ar+ar^2+ar^3+....... ar^n$

$r=$ the common ratio

Here, $r=6$

So, $S=sum_0^n2*6^n$

How do you write the series 2+12+72+432+25922+12+72+432+2592 using sigma notation?