How do you write the slope intercept form of the equation passing through the point (-6,5) and parallel to the line y=2x-2?

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Answer 1 · 2015-04-01T19:12:24

The equation is #y=2x+17#

The general equation for a straight line is:

#y=mx+c#

So

#5=-6m+c#

The other line is parallel and has the same slope so #m=2#

So #5=-(6xx2)+c#

#c=17#

So the equation of the line is:

#y=2x+17#