How do you write the standard form of a line parallel to y-3x=2 and passing through (2,-4)?

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Answer 1 · 2017-04-07T09:36:39

#y-3x+10=0#

A line parallel to #ax+by+c=0# is of the type #ax+by+k=0#

As #y-3x=2# is #-3x+y-2=0#

a line parallel to it will of type #-3x+y+k=0#

Now as it passes through #(2,-4)#, we have

#-3xx2+(-4)+k=0#

or #k=6+4=10#

Hence equation is #-3x+y+10=0# or #y-3x+10=0#

graph{(y-3x+10)(y-3x-2)((x-2)^2+(y+4)^2-0.03)=0 [-9.17, 10.83, -6.48, 3.52]}