How do you write #x^2-2x=8# in standard form? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Alan P. May 3, 2015 Standard quadratic form #ax^2+bx+c=0# Given #x^2−2x=8# standard form: #x^2-2x-8 =0# Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 5667 views around the world You can reuse this answer Creative Commons License