How do you write #x-2y=2# in #y=mx+b# form?

Question

12238 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-11T04:00:27

We start off by transposing x to the Right Hand Side

#-2y= x + 2#

We can then divide both sides by #-2#

#(cancel(-2)y)/cancel(2)= (x + 2)/2#

#y = x/2 + 2/2#

#color(green)(y = (1/2)*x + 1#

The Slope of this line is #1/2# and it's Y intercept is #1#. It's graph will look like this:

graph{y = (1/2)*x + 1 [-10, 10, -5, 5]}