How do you write $x-3y= -18$ in slope intercept form?

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Answer 1 · 2016-08-14T16:50:14

$y = 1/3x +6$

Make $y$ the subject of the equation

$x - 3y = -18$

$x+18 = 3y" divide by 3"$

$y = 1/3x +6$

$y = mx + c$ is slope, y-intercept form

How do you write x-3y= -18x-3y= -18 in slope intercept form?