How do you write $x + 4y = -6$ into slope intercept form?

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Answer 1 · 2015-08-07T21:27:58

$y=-1/4x-3/2$

Subtract $x$ from both sides
$4y=-6-x$

Rewrite
$4y=-x-6$

Divide both sides by $4$
$y=(-x-6)/4$

Rewrite
$y=-1/4x-6/4$

Reduce $6/4$

$y=-1/4x-3/2$

How do you write x + 4y = -6x + 4y = -6 into slope intercept form?