How do you write #y-1=4/5(x+5)# in slope intercept form?

2 Answers
Dec 17, 2016

#y = 4/5x + 5#

Explanation:

The slope intercept for is: #color(red)(y = mx + b)#
Where #m# is the slope and #b# is the y-intercept.

We must solve the equation given for #y#:

#y - 1 = 4/5x + 4/5*5#

#y - 1 = 4/5x + 4/cancel(5)*cancel(5)#

#y - 1 = 4/5x + 4#

#y - 1 + 1 = 4/5x + 4 + 1#

#y - 0 = 4/5x + 5#

#y = 4/5x + 5#

Dec 17, 2016

#y=4/5x+5#

Explanation:

The equation of a line in #color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b, the y-intercept.

Begin with distributing the bracket.

#rArry-1=4/5x+4#

#rArry=4/5x+5larr" in slope-intercept form"#