How do you write $y + 2 = \frac{1}{6} (x - 4)$ $y+2=1/6(x-4)$ in slope intercept form?

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How do you write $y + 2 = \frac{1}{6} (x - 4)$ $y+2=1/6(x-4)$ in slope intercept form?

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Answer 1 · 2017-03-09T11:06:28

$y = \frac{1}{6} x - \frac{8}{3}$ $y=1/6x-8/3$

Explanation:

The equation of a line in $slope-intercept form$ $color(blue)"slope-intercept form"$ is.

$color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))$
where m represents the slope and b, the y-intercept.

$"Rearrange "y+2=1/6(x-4)" into this form"$

distribute bracket and simplify.

$y+2=1/6x-2/3$

$rArry=1/6x-2/3-2$

$rArry=1/6x-8/3larrcolor(red)" in slope-intercept form"$

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How do you write $y + 2 = \frac{1}{6} (x - 4)$ $y+2=1/6(x-4)$ in slope intercept form?

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How do you write $y + 2 = \frac{1}{6} (x - 4)$ $y+2=1/6(x-4)$ in slope intercept form?