How do you write $y - 2 = 4 (x - 3)$ $y-2=4(x-3)$ in slope intercept form?

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Answer 1 · 2017-01-12T14:02:37

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The slope-intercept form of a linear equation is:

$y = m x + b$ $y = color(red)(m)x + color(blue)(b)$

Where $m$ $color(red)(m)$ is the slope and $b$ $color(blue)(b$ is the y-intercept value.

Therefore, in order to transform this equation from point-slope form to slope-intercept form we must solve for $y$ $y$ :

$y - 2 = (4 \times x) - (4 \times 3)$ $y - 2 = (4 xx x) - (4 xx 3)$

$y - 2 = 4 x - 12$ $y - 2 = 4x - 12$

$y - 2 + 2 = 4 x - 12 + 2$ $y - 2 + color(red)(2) = 4x - 12 + color(red)(2)$

$y - 0 = 4 x - 10$ $y - 0 = 4x - 10$

$y = 4 x - 10$ $y = 4x - 10$

$y = 4 x + 10$ $y = color(red)(4)x + color(blue)(10)$

How do you write y−2=4(x−3)y-2=4(x-3) in slope intercept form?