How do you write #y+4=3(3x+3)# in slope intercept form?

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Answer 1 · 2017-02-03T16:42:41

#y = color(red)(9)x + color(blue)(5)#

The slope-intercept form of a linear equation is:

#y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

Solving for #y# gives:

#y + 4 = (3 xx 3x) + (3 xx 3)#

#y + 4 = 9x + 9#

#y + 4 - color(red)(4) = 9x + 9 - color(red)(4)#

#y + 0 = 9x + 5#

#y = 9x + 5#