How do you write $y + 6 = - \frac{3}{4} (x + 8)$ $y+6=-3/4(x+8)$ in slope intercept form?

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Answer 1 · 2017-07-15T02:51:50

See a solution process below:

The slope-intercept form of a linear equation is: $y = m x + b$ $y = color(red)(m)x + color(blue)(b)$

Where $m$ $color(red)(m)$ is the slope and $b$ $color(blue)(b)$ is the y-intercept value.

Therefore we must solve this equation for $y$ $y$ :

$y + 6 = - \frac{3}{4} (x + 8)$ $y + 6 = -3/4(x + 8)$

$y + 6 = (- \frac{3}{4} \times x) + (- \frac{3}{4} \times 8)$ $y + 6 = (-3/4 xx x) + (-3/4 xx 8)$

$y + 6 = -3/4x + (-3/color(red)(cancel(color(black)(4))) xx color(red)(cancel(color(black)(8)))2)$

$y + 6 = -3/4x + (-6)$

$y + 6 = -3/4x - 6$

$y + 6 - color(red)(6) = -3/4x - 6 - color(red)(6)$

$y + 0 = -3/4x - 12$

$y = color(red)(-3/4)x - color(blue)(12)$

How do you write y+6=-3/4(x+8)y+6=−34(x+8)y+6=-3/4(x+8) in slope intercept form?