How does $\frac{9 π}{8}$ $(9π)/8$ rad = 202.5° ?

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Answer 1 · 2015-06-24T03:09:39

9pi/8 = 202.5 deg

$pi -> 180$ deg

$9pi/8 -> (180/pi).((9pi)/8) =$ 202.5 deg

How does (9π)/89π8(9π)/8 rad = 202.5° ?