How is the following solved? Is there reciprocation?

(a/b+c/d) divide (a/b-c/d) (ab+cd)÷(abcd)

1 Answer
May 11, 2018

(ad+bc)/(ad-bc)ad+bcadbc

Explanation:

"simplify each factor"simplify each factor

rArr(ad+bc)/(bd)" and "(ad-bc)/(bd)ad+bcbd and adbcbd

"change "-:" to "xx" and invert second fraction"change ÷ to × and invert second fraction

rArr(ad+bc)/cancel(bd)xxcancel(bd)/(ad-bc)=(ad+bc)/(ad-bc)