How is the function #1/9*x^3 +5, x<-3# not continuous at x=1 and what type of correspondence does it display?

1 Answer
Jan 9, 2018

Please see below.

Explanation:

For #f(x) = 1/9x^3+5#, for #x < -3#, the domain is #(-oo,-3)#

Therefore #f# is not defined at #x-1# so it cannot be continuous there.

Since #f'(x) = 1/3 x^2# is always positive, the function is a one to one correspondence.