How is the speed of a wave determined for this question?

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How is the speed of a wave determined for this question?

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Answer 1 · 2016-05-12T09:58:12

The distance from peak to trough is $48$ $48$ $c m = 0.48$ $cm=0.48$ $m$ $m$ , so a full wavelength, $λ$ $lambda$ , is twice this much, $0.96$ $0.96$ $m$ $m$ . The frequency is given as $2.4$ $2.4$ $H z$ $Hz$ .

For a wave, $v = f λ = 2.4 \times 0.96 = 2.304 \approx 2.3$ $v=flambda=2.4xx0.96=2.304~~2.3$ $m s^{- 1}$ $ms^-1$ .

Explanation:

The equation $v = f λ$ $v=flambda$ connects the velocity in $m s^{- 1}$ $ms^-1$ with the wavelength, $λ$ $lambda$ , in $m$ $m$ and the frequency in $H z$ $Hz$ .

$H z$ $Hz$ (hertz) is the unit of frequency, and is equivalent to $s^{- 1}$ $s^-1$ in SI units.

This means the units are consistent on both sides.

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How is the speed of a wave determined for this question?

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