How many atoms are in 1.92 mol #KMnO_4#?

1 Answer
anor277
Mar 3, 2016

#1# #mol# of particles specifies Avogadro's number of particles, so #"no. of atoms" = N_Axx1.92*molxx6" atoms "mol^-1*KMnO_4#.

Explanation:

So, #N_A#, Avogadro's number, specifies #6.022xx10^23# #mol^-1#.

You have quoted a #1.92# #"mole"# quantity. This specifies #1.92# #"mole"# #xx# #6.022xx10^23# #mol^-1# individual #KMnO_4# units.

Now each #KMnO_4# unit comprises #6# atoms. So simply multiply the molar quantity by 6

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