How many grams of $C a O$ $CaO$ can be formed from the decomposition of 275 g of $C a C O_{3}$ $CaCO_3$ ?

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Answer 1 · 2017-01-07T19:45:07

Approx. $150 \cdot g$ $150*g$ $calcium oxide$ $"calcium oxide"$ will be isolated given stoichiometric reaction.

We need (i) a stoichiometric equation:

$CaCO_3(s) + Delta rarr CaO(s) + CO_2(g)$

And (ii) equivalent quantities of $"calcium carbonate"$ ,

$"Moles of calcium carbonate"=(275*g)/(100.09*g*mol^-1)=2.75*mol$

And thus $2.75*molxx56.08*g*mol^-1=??*g$ $"calcium oxide"$ .

Why is there $"1:1"$ equivalence between $"calcium oxide"$ and $"calcium carbonate"$ .

How many grams of CaOCaOCaO can be formed from the decomposition of 275 g of CaCO_3CaCO3CaCO_3?