How many grams of carbon monoxide can you produce from 3 grams of carbon and an excess of oxygen?

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How many grams of carbon monoxide can you produce from 3 grams of carbon and an excess of oxygen?

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Answer 1 · 2016-08-28T19:41:00

About $7$ $7$ $g$ $g$ of $C O$ $CO$ ,

Explanation:

We need (i) a stoichiometric equation:

$C (s) + \frac{1}{2} O_{2} (g) \to C O (g)$ $C(s) +1/2O_2(g) rarr CO(g)$

And now (ii) we need the equivalent quantity of $C$ $C$ .

$Moles of carbon$ $"Moles of carbon"$ $=$ $=$ $\frac{3.0 \cdot g}{12.011 \cdot g \cdot m o l^{- 1}}$ $(3.0*g)/(12.011*g*mol^-1)$ $=$ $=$ $\frac{1}{4} \cdot mole$ $1/4*"mole"$ .

So mass of carbon monoxide $=$ $=$ $\frac{1}{4} \cdot m o l \times 28 \cdot g \cdot m o l^{- 1}$ $1/4*molxx28*g*mol^-1$ $=$ $=$ $7 \cdot g$ $7*g$ .

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How many grams of carbon monoxide can you produce from 3 grams of carbon and an excess of oxygen?

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