How many grams of nitrogen dioxide must react with water to produce $5.00 \cdot 10^{22}$ $5.00*10^22$ molecules of nitrogen monoxide?

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Answer 1 · 2016-12-06T05:06:54

11.46 grams

Consider the balanced chemical equation, which we need to obtain the molar ratios:

$3 N O_{2} + H_{2} O \to N O + 2 H N O_{3}$ $3NO_2+H_2O -> NO + 2HNO_3$

I see you would like to know the grams $N O_{2}$ $NO_2$ required to react with your amount of atoms $N O$ $NO$ .

Let's use the molar ratios to calculate the amount of nitrogen dioxide required.

Consider the graphic below:
enter image source here

How many grams of nitrogen dioxide must react with water to produce 5.00⋅10225.00*10^22 molecules of nitrogen monoxide?