How many grams of oxygen gas present in a 2.50-L sample kept at 1.66 atm pressure and a temperature of 10.0°C?

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How many grams of oxygen gas present in a 2.50-L sample kept at 1.66 atm pressure and a temperature of 10.0°C?

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Answer 1 · 2016-05-26T05:49:06

Approx. $0.2 \cdot m o l$ $0.2*mol$

Explanation:

We use the Ideal Gas equation: $P V = n R T$ $PV=nRT$ , and the appropriate gas constant $R$ $R$ .

$n$ $n$ $=$ $=$ $\frac{P V}{R T}$ $(PV)/(RT)$ $=$ $=$ $\frac{1.66 \cdot a t m \times 2.50 \cdot L}{0.0821 \cdot L \cdot a t m \cdot K^{- 1} \cdot m o l^{- 1} \times 283 \cdot K}$ $(1.66*atmxx2.50*L)/(0.0821*L*atm*K^-1*mol^-1xx283*K)$

$≅$ $~=$ $0.20 \cdot m o l$ $0.20*mol$

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How many grams of oxygen gas present in a 2.50-L sample kept at 1.66 atm pressure and a temperature of 10.0°C?

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