How many grams of potassium carbonate are needed to make 200 mL of a 2.5 M solution?

1 Answer
anor277
Mar 12, 2016

We need approx. #70# #g# of potassium carbonate.

Explanation:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution (L)"#

Thus, #"Moles of solute"# #=#

#"Concentration "xx" Volume of solution"#

#2.50*mol*L^-1xx0.200*L# #=# #0.500*mol#

#0.500*cancel(mol)xx138.21*g*cancel(mol^-1)" potassium carbonate"# #=# #??g" potassium carbonate"#

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