How many grams of $TiCl_4$ are needed to produce 44.9 g of titanium?

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Answer 1 · 2017-01-05T20:51:49

At least $178*g$ of $"titanic chloride"$ are required...........

$"Moles of titanium"$ $=$ $(44.9*g)/(47.87*g*mol^-1)=0.938*mol.$

And thus we need AT LEAST an equimolar quantity of $TiCl_4$ .

And this represents of equivalent mass of:

$0.938*molxx189.68*g*mol^-1=??*g.$

I think the industrial process utilizes either alkali metals or alkaline earth metals to reduce the $TiCl_4$ .

How many grams of TiCl_4TiCl_4 are needed to produce 44.9 g of titanium?