How many liters do 3.60xx10^(24)3.60×1024 molecules of "O"_2O2 occupy at STP?

1 Answer
May 28, 2017

The "molar volume at STP"molar volume at STP is 22.4*L22.4L......And thus there are approx. 134*L134L of oxygen gas........

Explanation:

So to address your question, we (i) work out the molar quantity of "dioxygen gas......."dioxygen gas.......

"Moles of dioxygen"Moles of dioxygen == (3.60xx10^24*"molecules")/(6.022xx10^23*"molecules"*mol^-1)3.60×1024molecules6.022×1023moleculesmol1 == 6.0*mol.6.0mol.

And then (ii) we take the product:

6.0*cancel(mol)xx22.4*L*cancel(mol^-1)=??

@Kathryn, the formatting here is sometimes infuriating.....you are not the only person to find it difficult.