Question

How many mL of a 2.00M `H_2SO_4` are needed to provide .250 mole of `H_2SO_4`?

Answer 1

Over `100*mL`.

Explanation:

`"Moles"` `=` `"Concentration"xx"Volume"`. This can be appreciated dimensionally, i.e. `mol*L^-1xxL=mol!`.

We require `0.250*mol`, and so we divide the required number of moles by the concentration to get the volume:

`(0.250*cancel(mol))/(2.00*cancel(mol)*cancel(L^-1))xx1000*mL*cancel(L^-1)` `=` `??mL`