How many molecules are there in 15.7 liters of chlorine gas at STP?

1 Answer
Apr 12, 2016

(15.7*L)/(22.414*L*mol^-1) xx N_A

Explanation:

We idealize the behaviour of this gas. And it is a fact that STP, 1 mole of an ideal gas has a volume of 22.414*L.

So we take the quotient, (15.7*L)/(22.414*L*mol^-1) to get a molar quantity, and multiply this amount by Avogadro's number to get the number of molecules.

(15.7*cancelL)/(22.414*cancelL*cancel(mol^-1)) xx 6.022xx10^23*cancel(mol^-1) = ??

How many individual chlorine atoms are there in this quantity?