How many moles are necessary to react completely with four moles of propane in the reaction $C_{3} H_{8} + 5 O_{2} \to 3 C O_{2} + 4 H_{2} O$ $C_3H_8 + 5O_2 -> 3CO_2 + 4H_2O$ ?

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Answer 1 · 2016-02-25T20:14:19

$20 m o l of O_{2}$ $20mol " of "O_2$

I assume that the question is about how many moles of oxygen that will react completely with four moles of propane.

From the balanced equation:

$C_{3} H_{8} + 5 O_{2} \to 3 C O_{2} + 4 H_{2} O$ $C_3H_8+5O_2->3CO_2+4H_2O$

Every 1 mole of $C_{3} H_{8}$ $C_3H_8$ reacts with 5 moles of $O_{2}$ $O_2$ , therefore,

$?molO_2=4cancel(molC_3H_8)xx(5molO_2)/(1cancel(molC_3H_8))=20 molO_2$

How many moles are necessary to react completely with four moles of propane in the reaction C_3H_8 + 5O_2 -> 3CO_2 + 4H_2OC3H8+5O2→3CO2+4H2OC_3H_8 + 5O_2 -> 3CO_2 + 4H_2O?