Question

How many moles of a gas would occupy `157` `L` at `132` `kPa` and `-16.8°C`?

Answer 1

First convert the temperature to kelvin: `273.15-16.8=256` `K`. The Ideal Gas Law says `PV=nRT` (where `R=8.314` `L kPa K^−1 mol^−1`). Rearranging, `n=(PV)/(RT)=(132*157)/(8.314*256)=9.74` `mol`.