How many moles of Al₂S₃ will you make if you have 4.3 x 10¹⁶ moles of Li₂S in the following equation?

Question

_ Li2S + _ AlCl3 → _ LiCl + _ Al2S3

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Answer 1 · 2018-03-17T23:25:52

Consider the balanced equation,

#3Li_2S + 2AlCl_3 to 6LiCl + Al_2S_3#

This is a simple stoichiometric calculation. We're relating stoichiometric coefficients to the molar quantity "reacted".

Hence,

#4.3*10^16"mol" * (Al_2S_3)/(3Li_2S) approx 1.4*10^16"mol"#

of #Al_2S_3# will be made from that amount of lithium sulfide assuming aluminum chloride is in excess.