How many moles of $C O$ $CO$ and $O_{2}$ $O_2$ are required to produce 10 moles of $C O_{2}$ $CO_2$ in the reaction $2 C O + O_{2} \to 2 C O_{2}$ $2CO + O_2 -> 2CO_2$ ?

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How many moles of $C O$ $CO$ and $O_{2}$ $O_2$ are required to produce 10 moles of $C O_{2}$ $CO_2$ in the reaction $2 C O + O_{2} \to 2 C O_{2}$ $2CO + O_2 -> 2CO_2$ ?

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Answer 1 · 2018-07-23T02:23:31

$10 mol CO$ $"10 mol CO"$ and ${5 mol O}_{2}$ $"5 mol O"_2"$ are required to produce ${10 mol CO}_{2}$ $"10 mol CO"_2"$ .

Explanation:

Balanced equation

$2CO (g) + O_{2} (g)$ $"2CO"("g") + "O"_2("g")"$ $\to$ $rarr$ ${2CO}_{2} (g)$ $"2CO"_2("g")"$

To calculate moles $CO$ $"CO"$ and $O_{2}$ $"O"_2"$ required to produce ${10 mol CO}_{2}$ $"10 mol CO"_2"$ , multiply mol ${CO}_{2}$ $"CO"_2"$ by the mol ratio between the desired reactant and ${CO}_{2}$ $"CO"_2"$ in the balanced equation, with the desired reactant in the numerator.

$10color(red)cancel(color(black)("mol CO"_2))xx(2"mol CO")/(2color(red)cancel(color(black)("mol CO"_2)))="10 mol CO"$

$10color(red)cancel(color(black)("mol CO"_2))xx(1"mol O"_2)/(2color(red)cancel(color(black)("mol CO"_2)))="5 mol O"_2"$

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How many moles of $C O$ $CO$ and $O_{2}$ $O_2$ are required to produce 10 moles of $C O_{2}$ $CO_2$ in the reaction $2 C O + O_{2} \to 2 C O_{2}$ $2CO + O_2 -> 2CO_2$ ?

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Explanation:

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How many moles of COCOCO and O_2O2O_2 are required to produce 10 moles of CO_2CO2CO_2 in the reaction 2CO + O_2 -> 2CO_22CO+O2→2CO22CO + O_2 -> 2CO_2?

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How many moles of $C O$ $CO$ and $O_{2}$ $O_2$ are required to produce 10 moles of $C O_{2}$ $CO_2$ in the reaction $2 C O + O_{2} \to 2 C O_{2}$ $2CO + O_2 -> 2CO_2$ ?